Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given
"egg"
, "add"
, return true.Given
"foo"
, "bar"
, return false.Given
"paper"
, "title"
, return true.Note:
You may assume both s and t have the same length.
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Solution: Maintain a two-way mapping (c1 <-> c2) between each character in the string in the same index. If we find that something was previous mapped but not matching the current characters in s and t, then the strings are not isomorphic. If we did not find any discrepancies, return true.
public class Solution {
public boolean isIsomorphic(String s, String t) {
if (s.length() != t.length()) return false;
Map<Integer, Integer> map1 = new HashMap<>();
Map<Integer, Integer> map2 = new HashMap<>();
for (int i = 0; i < s.length(); i++) {
int c1 = s.charAt(i);
int c2 = t.charAt(i);
Integer m1 = map1.get(c1);
if (m1 != null && m1 != c2) return false;
Integer m2 = map2.get(c2);
if (m2 != null && m2 != c1) return false;
map1.put(c1, c2);
map2.put(c2, c1);
}
return true;
}
}
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