Two binary trees are considered equal if they are structurally identical and the nodes have the same value.
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Solution: Check the current node, and then recurse using the same function for both the left and right children.
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public boolean isSameTree(TreeNode p, TreeNode q) {
if (p == q) return true;
if (p == null || q == null) return false;
if (p.val != q.val) return false;
return isSameTree(p.left, q.left) && isSameTree(p.right, q.right);
}
}
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