---
Solution: First get the head node as we will return that at the end. Then go through the nodes in l1 and l2, always adding the smaller node first.
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
public class Solution {
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
if (l1 == null && l2 == null) return null;
if (l1 == null) return l2;
if (l2 == null) return l1;
ListNode head;
if (l1.val < l2.val) {
head = l1;
l1 = l1.next;
} else {
head = l2;
l2 = l2.next;
}
ListNode curr = head;
while (true) {
if (l1 == null) {
curr.next = l2;
break;
}
if (l2 == null) {
curr.next = l1;
break;
}
if (l1.val < l2.val) {
curr.next = l1;
l1 = l1.next;
} else {
curr.next = l2;
l2 = l2.next;
}
curr = curr.next;
}
return head;
}
}
No comments:
Post a Comment